* and ++ operators c interview question


* and ++ operators c interview questions

Question: What would be the output of the following code and why?
#include

int main(void)
{
    char *ptr = "Linux";
    printf("\n [%c] \n",*ptr++);
    printf("\n [%c] \n",*ptr);

    return 0;
}
Answer: The output of the above would be :
[L] 

[i]
Since the priority of both ‘++’ and ‘*’ are same so processing of ‘*ptr++’ takes place from right to left. Going by this logic, ptr++ is evaluated first and then *ptr. So both these operations result in ‘L’. Now since a post fix ‘++’ was applied on ptr so the next printf() would print ‘i’.

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